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10x^2=-25x+125
We move all terms to the left:
10x^2-(-25x+125)=0
We get rid of parentheses
10x^2+25x-125=0
a = 10; b = 25; c = -125;
Δ = b2-4ac
Δ = 252-4·10·(-125)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-75}{2*10}=\frac{-100}{20} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+75}{2*10}=\frac{50}{20} =2+1/2 $
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